What are the solutions to the equation 2x^2-5x-18=0 ?

The solutions to the equation 2x^2-5x-18=0 are x= 9/2 ,x=-2

Find the zeros of 2x^2-5x-18=0

The zeros of 2x^2-5x-18=0 are x= 9/2 ,x=-2

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2 x^{2} - 5 x - 18 = 0

x = \frac{9}{2}, x = - 2

Solution steps

2 x^{2} - 5 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 18 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 18) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 2}

x = \frac{- ( - 5 ) + 13}{2 \cdot 2} : \frac{9}{2}

x = \frac{- ( - 5 ) - 13}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = - 2

x^{4} - 5 x^{3} - 9 x^{2} + 81 x - 108

1 - 3

x^{2} < 4 (x + 3)

3 (a + 10) = 6 (a + 5) - 3 a

x^{\frac{3}{2}} \cdot x^{\frac{3}{2}}

What are the solutions to the equation 2x^2-5x-18=0 ?
The solutions to the equation 2x^2-5x-18=0 are x= 9/2 ,x=-2
Find the zeros of 2x^2-5x-18=0
The zeros of 2x^2-5x-18=0 are x= 9/2 ,x=-2