What are the solutions to the equation x^2-22x+121=0 ?

The solutions to the equation x^2-22x+121=0 are x=11

Find the zeros of x^2-22x+121=0

The zeros of x^2-22x+121=0 are x=11

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x^{2} - 22 x + 121 = 0

x = 11

Solution steps

x^{2} - 22 x + 121 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 22 ) \pm ( - 22 ) ^{2} - 4 \cdot 1 \cdot 121}{2 \cdot 1}

(- 22)^{2} - 4 \cdot 1 \cdot 121 = 0

x_{1, 2} = \frac{- ( - 22 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 22 )}{2 \cdot 1}

\frac{- ( - 22 )}{2 \cdot 1} = 11

x = 11

The solution to the quadratic equation is:

x = 11

x - \frac{2}{5} = \frac{3}{10}

x + 7 = - \frac{1}{4} (8 x - 12)

∣ 2 x - 7 ∣ = 3

\frac{2 3}{2}

4 h^{2} + 4 h + 1 = 0

What are the solutions to the equation x^2-22x+121=0 ?
The solutions to the equation x^2-22x+121=0 are x=11
Find the zeros of x^2-22x+121=0
The zeros of x^2-22x+121=0 are x=11