What are the solutions to the equation 6x^2+x-5=0 ?

The solutions to the equation 6x^2+x-5=0 are x= 5/6 ,x=-1

Find the zeros of 6x^2+x-5=0

The zeros of 6x^2+x-5=0 are x= 5/6 ,x=-1

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6 x^{2} + x - 5 = 0

x = \frac{5}{6}, x = - 1

Decimal Notation

x = 0.83333 \dots, x = - 1

Solution steps

6 x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 5) = 11

x_{1, 2} = \frac{- 1 \pm 11}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 11}{2 \cdot 6}, x_{2} = \frac{- 1 - 11}{2 \cdot 6}

x = \frac{- 1 + 11}{2 \cdot 6} : \frac{5}{6}

x = \frac{- 1 - 11}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

x = \frac{5}{6}, x = - 1

16 x^{2} - 22 x + 5 = 2 x

\frac{z}{2} \leq 3

\frac{2 ( 3 x - 1 )}{3} + \frac{5 x - 6}{6} = \frac{138}{9}

\frac{e ^{2 x}}{e ^{- x}}

6 - 6 x^{2} = 3 x

What are the solutions to the equation 6x^2+x-5=0 ?
The solutions to the equation 6x^2+x-5=0 are x= 5/6 ,x=-1
Find the zeros of 6x^2+x-5=0
The zeros of 6x^2+x-5=0 are x= 5/6 ,x=-1