What are the solutions to the equation 6-6x^2=3x ?

The solutions to the equation 6-6x^2=3x are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4

Find the zeros of 6-6x^2=3x

The zeros of 6-6x^2=3x are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4

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6 - 6 x^{2} = 3 x

x = - \frac{1 + 17}{4}, x = \frac{17 - 1}{4}

Solution steps

6 - 6 x^{2} = 3 x

Move

3 x

to the left side

6 - 6 x^{2} - 3 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} - 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 6 ) \cdot 6}{2 ( - 6 )}

(- 3)^{2} - 4 (- 6) \cdot 6 = 317

x_{1, 2} = \frac{- ( - 3 ) \pm 3 17}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 17}{2 ( - 6 )}, x_{2} = \frac{- ( - 3 ) - 3 17}{2 ( - 6 )}

x = \frac{- ( - 3 ) + 3 17}{2 ( - 6 )} : - \frac{1 + 17}{4}

x = \frac{- ( - 3 ) - 3 17}{2 ( - 6 )} : \frac{17 - 1}{4}

The solutions to the quadratic equation are:

x = - \frac{1 + 17}{4}, x = \frac{17 - 1}{4}

\frac{3.3 \cdot 0.343}{2.1}

\frac{x ^{- 2}}{x ^{- 1}}

4 x^{2} - 5 x + 24 = 0

1 - \frac{1}{\frac{1}{a}}

∣ x + 1 ∣ + 5 \geq 7

What are the solutions to the equation 6-6x^2=3x ?
The solutions to the equation 6-6x^2=3x are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4
Find the zeros of 6-6x^2=3x
The zeros of 6-6x^2=3x are x=-(1+sqrt(17))/4 ,x=(sqrt(17)-1)/4