What are the solutions to the equation 0=-1/9 (y+1)^2-3 ?

The solutions to the equation 0=-1/9 (y+1)^2-3 are y=3sqrt(3)i-1,y=-3sqrt(3)i-1

Find the zeros of 0=-1/9 (y+1)^2-3

The zeros of 0=-1/9 (y+1)^2-3 are y=3sqrt(3)i-1,y=-3sqrt(3)i-1

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0 = - \frac{1}{9} (y + 1)^{2} - 3

y = 33 i - 1, y = - 33 i - 1

Solution steps

0 = - \frac{1}{9} (y + 1)^{2} - 3

Switch sides

- \frac{1}{9} (y + 1)^{2} - 3 = 0

Move

3

to the right side

- \frac{1}{9} (y + 1)^{2} = 3

Multiply both sides by

- 9

(y + 1)^{2} = - 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 1 = - 27 : y = 33 i - 1

Solve

y + 1 = - - 27 : y = - 33 i - 1

The solutions to the quadratic equation are:

y = 33 i - 1, y = - 33 i - 1

- \frac{1}{2} x - (- 3) - x = 15

6 b^{2} - 5 b = 4

\frac{x}{7} = - 3

1 - e^{- \frac{80}{25}}

24 = 3 - (- x - 16)

What are the solutions to the equation 0=-1/9 (y+1)^2-3 ?
The solutions to the equation 0=-1/9 (y+1)^2-3 are y=3sqrt(3)i-1,y=-3sqrt(3)i-1
Find the zeros of 0=-1/9 (y+1)^2-3
The zeros of 0=-1/9 (y+1)^2-3 are y=3sqrt(3)i-1,y=-3sqrt(3)i-1