What are the solutions to the equation 6b^2-5b=4 ?

The solutions to the equation 6b^2-5b=4 are b= 4/3 ,b=-1/2

Find the zeros of 6b^2-5b=4

The zeros of 6b^2-5b=4 are b= 4/3 ,b=-1/2

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6 b^{2} - 5 b = 4

b = \frac{4}{3}, b = - \frac{1}{2}

Solution steps

6 b^{2} - 5 b = 4

Move

4

to the left side

6 b^{2} - 5 b - 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

(- 5)^{2} - 4 \cdot 6 (- 4) = 11

b_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 6}

Separate the solutions

b_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 6}, b_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 6}

b = \frac{- ( - 5 ) + 11}{2 \cdot 6} : \frac{4}{3}

b = \frac{- ( - 5 ) - 11}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

b = \frac{4}{3}, b = - \frac{1}{2}

\frac{x}{7} = - 3

1 - e^{- \frac{80}{25}}

24 = 3 - (- x - 16)

4 p^{2} - p = 0

3 x - 15 = 2 x + 5

What are the solutions to the equation 6b^2-5b=4 ?
The solutions to the equation 6b^2-5b=4 are b= 4/3 ,b=-1/2
Find the zeros of 6b^2-5b=4
The zeros of 6b^2-5b=4 are b= 4/3 ,b=-1/2