What are the solutions to the equation x^2-8x-12=36 ?

The solutions to the equation x^2-8x-12=36 are x=12,x=-4

Find the zeros of x^2-8x-12=36

The zeros of x^2-8x-12=36 are x=12,x=-4

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x^{2} - 8 x - 12 = 36

x = 12, x = - 4

Solution steps

x^{2} - 8 x - 12 = 36

Move

36

to the left side

x^{2} - 8 x - 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 48 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 48) = 16

x_{1, 2} = \frac{- ( - 8 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 16}{2 \cdot 1}

x = \frac{- ( - 8 ) + 16}{2 \cdot 1} : 12

x = \frac{- ( - 8 ) - 16}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 12, x = - 4

(- 3 a b^{2})^{3}

\frac{2 + 5 i}{5 - 2 i}

x^{3} - 8 x + 8

0 = x^{2} - 2 x - 3

4 x^{2} - 2 x - 12 = 0

What are the solutions to the equation x^2-8x-12=36 ?
The solutions to the equation x^2-8x-12=36 are x=12,x=-4
Find the zeros of x^2-8x-12=36
The zeros of x^2-8x-12=36 are x=12,x=-4