What are the solutions to the equation 4x^2-2x-12=0 ?

The solutions to the equation 4x^2-2x-12=0 are x=2,x=-3/2

Find the zeros of 4x^2-2x-12=0

The zeros of 4x^2-2x-12=0 are x=2,x=-3/2

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4 x^{2} - 2 x - 12 = 0

x = 2, x = - \frac{3}{2}

Solution steps

4 x^{2} - 2 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 4 ( - 12 )}{2 \cdot 4}

(- 2)^{2} - 4 \cdot 4 (- 12) = 14

x_{1, 2} = \frac{- ( - 2 ) \pm 14}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 14}{2 \cdot 4}, x_{2} = \frac{- ( - 2 ) - 14}{2 \cdot 4}

x = \frac{- ( - 2 ) + 14}{2 \cdot 4} : 2

x = \frac{- ( - 2 ) - 14}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{2}

- 15 \cdot - 5

(\frac{3 t ^{6} u ^{2} v ^{5}}{9 t u v ^{21}})^{0}

4^{- x}

4 x^{2} + 25 = 0

\frac{81}{4}

What are the solutions to the equation 4x^2-2x-12=0 ?
The solutions to the equation 4x^2-2x-12=0 are x=2,x=-3/2
Find the zeros of 4x^2-2x-12=0
The zeros of 4x^2-2x-12=0 are x=2,x=-3/2