What are the solutions to the equation x^2+16x=-139 ?

The solutions to the equation x^2+16x=-139 are x=-8+5sqrt(3)i,x=-8-5sqrt(3)i

Find the zeros of x^2+16x=-139

The zeros of x^2+16x=-139 are x=-8+5sqrt(3)i,x=-8-5sqrt(3)i

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x^{2} + 16 x = - 139

x = - 8 + 53 i, x = - 8 - 53 i

Solution steps

x^{2} + 16 x = - 139

Move

139

to the left side

x^{2} + 16 x + 139 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot 139}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot 139 : 103 i

x_{1, 2} = \frac{- 16 \pm 10 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 10 3 i}{2 \cdot 1}, x_{2} = \frac{- 16 - 10 3 i}{2 \cdot 1}

x = \frac{- 16 + 10 3 i}{2 \cdot 1} : - 8 + 53 i

x = \frac{- 16 - 10 3 i}{2 \cdot 1} : - 8 - 53 i

The solutions to the quadratic equation are:

x = - 8 + 53 i, x = - 8 - 53 i

- 2 x + 6 = 24

4 x^{1} < - 11

x^{2} + x - 31 = 0

- 3 + 2 x > 9

\frac{98}{2 ^{\frac{1}{2}}}

What are the solutions to the equation x^2+16x=-139 ?
The solutions to the equation x^2+16x=-139 are x=-8+5sqrt(3)i,x=-8-5sqrt(3)i
Find the zeros of x^2+16x=-139
The zeros of x^2+16x=-139 are x=-8+5sqrt(3)i,x=-8-5sqrt(3)i