What are the solutions to the equation 6b^2-12b-90=0 ?

The solutions to the equation 6b^2-12b-90=0 are b=5,b=-3

Find the zeros of 6b^2-12b-90=0

The zeros of 6b^2-12b-90=0 are b=5,b=-3

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6 b^{2} - 12 b - 90 = 0

b = 5, b = - 3

Solution steps

6 b^{2} - 12 b - 90 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 6 ( - 90 )}{2 \cdot 6}

(- 12)^{2} - 4 \cdot 6 (- 90) = 48

b_{1, 2} = \frac{- ( - 12 ) \pm 48}{2 \cdot 6}

Separate the solutions

b_{1} = \frac{- ( - 12 ) + 48}{2 \cdot 6}, b_{2} = \frac{- ( - 12 ) - 48}{2 \cdot 6}

b = \frac{- ( - 12 ) + 48}{2 \cdot 6} : 5

b = \frac{- ( - 12 ) - 48}{2 \cdot 6} : - 3

The solutions to the quadratic equation are:

b = 5, b = - 3

- 3 x^{2} - 15 + 5 x = 4

2 x < 10

- \frac{22}{2}

\frac{2}{2 ^{- 4}}

- \frac{4}{5} y \leq 12

What are the solutions to the equation 6b^2-12b-90=0 ?
The solutions to the equation 6b^2-12b-90=0 are b=5,b=-3
Find the zeros of 6b^2-12b-90=0
The zeros of 6b^2-12b-90=0 are b=5,b=-3