What are the solutions to the equation x^2+8x+13=0 ?

The solutions to the equation x^2+8x+13=0 are x=-4+sqrt(3),x=-4-sqrt(3)

Find the zeros of x^2+8x+13=0

The zeros of x^2+8x+13=0 are x=-4+sqrt(3),x=-4-sqrt(3)

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x^{2} + 8 x + 13 = 0

x = - 4 + 3, x = - 4 - 3

Solution steps

x^{2} + 8 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 13 = 23

x_{1, 2} = \frac{- 8 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 3}{2 \cdot 1}

x = \frac{- 8 + 2 3}{2 \cdot 1} : - 4 + 3

x = \frac{- 8 - 2 3}{2 \cdot 1} : - 4 - 3

The solutions to the quadratic equation are:

x = - 4 + 3, x = - 4 - 3

- 4 x^{2} + 1040 x - 65100 = 0

5 y + 25

50 = 0.1 x + 45.5

lo g_{3} (729) = x

\frac{3}{2} (8)

What are the solutions to the equation x^2+8x+13=0 ?
The solutions to the equation x^2+8x+13=0 are x=-4+sqrt(3),x=-4-sqrt(3)
Find the zeros of x^2+8x+13=0
The zeros of x^2+8x+13=0 are x=-4+sqrt(3),x=-4-sqrt(3)