What are the solutions to the equation 0=2x^2+2x-1 ?

The solutions to the equation 0=2x^2+2x-1 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

Find the zeros of 0=2x^2+2x-1

The zeros of 0=2x^2+2x-1 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2

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0 = 2 x^{2} + 2 x - 1

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

Solution steps

0 = 2 x^{2} + 2 x - 1

Switch sides

2 x^{2} + 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 1) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 2}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 2}

x = \frac{- 2 + 2 3}{2 \cdot 2} : \frac{- 1 + 3}{2}

x = \frac{- 2 - 2 3}{2 \cdot 2} : - \frac{1 + 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 3}{2}, x = - \frac{1 + 3}{2}

5^{2} + 6^{2} = c^{2}

\frac{x}{3} + 8 = - 2

27 c^{3} + 125

∣ x + 3 ∣ < - 10

p^{2} + 4 p + 1 = 0

What are the solutions to the equation 0=2x^2+2x-1 ?
The solutions to the equation 0=2x^2+2x-1 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2
Find the zeros of 0=2x^2+2x-1
The zeros of 0=2x^2+2x-1 are x=(-1+sqrt(3))/2 ,x=-(1+sqrt(3))/2