What are the solutions to the equation p^2+4p+1=0 ?

The solutions to the equation p^2+4p+1=0 are p=-2+sqrt(3),p=-2-sqrt(3)

Find the zeros of p^2+4p+1=0

The zeros of p^2+4p+1=0 are p=-2+sqrt(3),p=-2-sqrt(3)

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p^{2} + 4 p + 1 = 0

p = - 2 + 3, p = - 2 - 3

Solution steps

p^{2} + 4 p + 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 1 = 23

p_{1, 2} = \frac{- 4 \pm 2 3}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 4 + 2 3}{2 \cdot 1}, p_{2} = \frac{- 4 - 2 3}{2 \cdot 1}

p = \frac{- 4 + 2 3}{2 \cdot 1} : - 2 + 3

p = \frac{- 4 - 2 3}{2 \cdot 1} : - 2 - 3

The solutions to the quadratic equation are:

p = - 2 + 3, p = - 2 - 3

224 t - 16 t^{2} = 0

\frac{( π + 1 ) ^{100}}{( π - 1 ) ^{100}}

7 = \frac{1}{6} (8 x + 24)

2 c + 10 \geq 4

What are the solutions to the equation p^2+4p+1=0 ?
The solutions to the equation p^2+4p+1=0 are p=-2+sqrt(3),p=-2-sqrt(3)
Find the zeros of p^2+4p+1=0
The zeros of p^2+4p+1=0 are p=-2+sqrt(3),p=-2-sqrt(3)