What are the solutions to the equation 6x^2+10x=-1 ?

The solutions to the equation 6x^2+10x=-1 are x=(-5+sqrt(19))/6 ,x=-(5+sqrt(19))/6

Find the zeros of 6x^2+10x=-1

The zeros of 6x^2+10x=-1 are x=(-5+sqrt(19))/6 ,x=-(5+sqrt(19))/6

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6 x^{2} + 10 x = - 1

x = \frac{- 5 + 19}{6}, x = - \frac{5 + 19}{6}

Decimal Notation

x = - 0.10685 \dots, x = - 1.55981 \dots

Solution steps

6 x^{2} + 10 x = - 1

Move

1

to the left side

6 x^{2} + 10 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 6 \cdot 1}{2 \cdot 6}

1 0^{2} - 4 \cdot 6 \cdot 1 = 219

x_{1, 2} = \frac{- 10 \pm 2 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 10 + 2 19}{2 \cdot 6}, x_{2} = \frac{- 10 - 2 19}{2 \cdot 6}

x = \frac{- 10 + 2 19}{2 \cdot 6} : \frac{- 5 + 19}{6}

x = \frac{- 10 - 2 19}{2 \cdot 6} : - \frac{5 + 19}{6}

The solutions to the quadratic equation are:

x = \frac{- 5 + 19}{6}, x = - \frac{5 + 19}{6}

5 ∣ 2 x + 4 ∣ - 3 = - 3

3 lo g_{3} (8)

7 x - 22 = - 85

- x^{2} + 10 x - 25 = 0

\frac{( - 6 a ^{5} b ) ^{2}}{12 a ^{7} b} - 8 a^{3} b

What are the solutions to the equation 6x^2+10x=-1 ?
The solutions to the equation 6x^2+10x=-1 are x=(-5+sqrt(19))/6 ,x=-(5+sqrt(19))/6
Find the zeros of 6x^2+10x=-1
The zeros of 6x^2+10x=-1 are x=(-5+sqrt(19))/6 ,x=-(5+sqrt(19))/6