What are the solutions to the equation 100=4pir^2 ?

The solutions to the equation 100=4pir^2 are r= 5/(sqrt(pi)),r=-5/(sqrt(pi))

Find the zeros of 100=4pir^2

The zeros of 100=4pir^2 are r= 5/(sqrt(pi)),r=-5/(sqrt(pi))

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100 = 4 π r^{2}

r = \frac{5}{π}, r = - \frac{5}{π}

Decimal Notation

r = 2.82094 \dots, r = - 2.82094 \dots

Solution steps

100 = 4 π r^{2}

Switch sides

4 π r^{2} = 100

Divide both sides by

4 π

r^{2} = \frac{25}{π}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = \frac{25}{π}, r = - \frac{25}{π}

\frac{25}{π} = \frac{5}{π}

- \frac{25}{π} = - \frac{5}{π}

r = \frac{5}{π}, r = - \frac{5}{π}

n^{2} - n - 36 = 0

3 x^{2} - 12 x + 11 = 0

\frac{x}{19} = 4

- 88 = 11 r

385

What are the solutions to the equation 100=4pir^2 ?
The solutions to the equation 100=4pir^2 are r= 5/(sqrt(pi)),r=-5/(sqrt(pi))
Find the zeros of 100=4pir^2
The zeros of 100=4pir^2 are r= 5/(sqrt(pi)),r=-5/(sqrt(pi))