What are the solutions to the equation u^2-9u+20=0 ?

The solutions to the equation u^2-9u+20=0 are u=5,u=4

Find the zeros of u^2-9u+20=0

The zeros of u^2-9u+20=0 are u=5,u=4

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u^{2} - 9 u + 20 = 0

u = 5, u = 4

Solution steps

u^{2} - 9 u + 20 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

u_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, u_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

u = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

u = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

u = 5, u = 4

(x + 5) (x - 7) \geq 0

- 2 p^{2} - 5 p + 7 = 0

4 - x < 9

lo g_{5} (5^{2})

1 + 25 a^{2} = 2

What are the solutions to the equation u^2-9u+20=0 ?
The solutions to the equation u^2-9u+20=0 are u=5,u=4
Find the zeros of u^2-9u+20=0
The zeros of u^2-9u+20=0 are u=5,u=4