What are the solutions to the equation 1+25a^2=2 ?

The solutions to the equation 1+25a^2=2 are a= 1/5 ,a=-1/5

Find the zeros of 1+25a^2=2

The zeros of 1+25a^2=2 are a= 1/5 ,a=-1/5

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1 + 25 a^{2} = 2

a = \frac{1}{5}, a = - \frac{1}{5}

Decimal Notation

a = 0.2, a = - 0.2

Solution steps

1 + 25 a^{2} = 2

Move

1

to the right side

25 a^{2} = 1

Divide both sides by

25

a^{2} = \frac{1}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = \frac{1}{25}, a = - \frac{1}{25}

\frac{1}{25} = \frac{1}{5}

- \frac{1}{25} = - \frac{1}{5}

a = \frac{1}{5}, a = - \frac{1}{5}

25 p^{2} - 40 p + 16 = 0

x + 2 = x + 4

k^{2} - 16 h^{2}

(e^{x} - e^{- x})^{2}

What are the solutions to the equation 1+25a^2=2 ?
The solutions to the equation 1+25a^2=2 are a= 1/5 ,a=-1/5
Find the zeros of 1+25a^2=2
The zeros of 1+25a^2=2 are a= 1/5 ,a=-1/5