What are the solutions to the equation x^2-2x=8 ?

The solutions to the equation x^2-2x=8 are x=4,x=-2

Find the zeros of x^2-2x=8

The zeros of x^2-2x=8 are x=4,x=-2

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x^{2} - 2 x = 8

x = 4, x = - 2

Solution steps

x^{2} - 2 x = 8

Move

8

to the left side

x^{2} - 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

x = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 4, x = - 2

1 < 1 - \frac{1}{5} x < 4

- 10 (10 + x) = - 110

\frac{1}{3} (a + 4) + 6 = \frac{1}{4} (3 a - 1) - 2

n^{2} - 13 n + 36 = 0

26 x - 3 \leq 23 x + 4 \leq 15 x + 10

What are the solutions to the equation x^2-2x=8 ?
The solutions to the equation x^2-2x=8 are x=4,x=-2
Find the zeros of x^2-2x=8
The zeros of x^2-2x=8 are x=4,x=-2