What are the solutions to the equation n^2-13n+36=0 ?

The solutions to the equation n^2-13n+36=0 are n=9,n=4

Find the zeros of n^2-13n+36=0

The zeros of n^2-13n+36=0 are n=9,n=4

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n^{2} - 13 n + 36 = 0

n = 9, n = 4

Solution steps

n^{2} - 13 n + 36 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 36 = 5

n_{1, 2} = \frac{- ( - 13 ) \pm 5}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 13 ) + 5}{2 \cdot 1}, n_{2} = \frac{- ( - 13 ) - 5}{2 \cdot 1}

n = \frac{- ( - 13 ) + 5}{2 \cdot 1} : 9

n = \frac{- ( - 13 ) - 5}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

n = 9, n = 4

26 x - 3 \leq 23 x + 4 \leq 15 x + 10

\frac{7}{5} = \frac{x}{3}

3 (x + 2) (x - 2) = 5 x

\frac{1}{2} \cdot 6 \cdot 8

- 3 \leq \frac{2 - 2 x}{2} \leq 3

What are the solutions to the equation n^2-13n+36=0 ?
The solutions to the equation n^2-13n+36=0 are n=9,n=4
Find the zeros of n^2-13n+36=0
The zeros of n^2-13n+36=0 are n=9,n=4