What are the solutions to the equation 3(x+2)(x-2)=5x ?

The solutions to the equation 3(x+2)(x-2)=5x are x=3,x=-4/3

Find the zeros of 3(x+2)(x-2)=5x

The zeros of 3(x+2)(x-2)=5x are x=3,x=-4/3

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3 (x + 2) (x - 2) = 5 x

x = 3, x = - \frac{4}{3}

Solution steps

3 (x + 2) (x - 2) = 5 x

Expand

3 (x + 2) (x - 2) : 3 x^{2} - 12

3 x^{2} - 12 = 5 x

Move

5 x

to the left side

3 x^{2} - 12 - 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 12) = 13

x_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 3}

x = \frac{- ( - 5 ) + 13}{2 \cdot 3} : 3

x = \frac{- ( - 5 ) - 13}{2 \cdot 3} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = 3, x = - \frac{4}{3}

\frac{1}{2} \cdot 6 \cdot 8

- 3 \leq \frac{2 - 2 x}{2} \leq 3

x^{5} + 2 x^{3} + x

8 + 5 b - 2 b^{2} = 9

x^{2} - 3 x \leq 40

What are the solutions to the equation 3(x+2)(x-2)=5x ?
The solutions to the equation 3(x+2)(x-2)=5x are x=3,x=-4/3
Find the zeros of 3(x+2)(x-2)=5x
The zeros of 3(x+2)(x-2)=5x are x=3,x=-4/3