What are the solutions to the equation 6x^2=27 ?

The solutions to the equation 6x^2=27 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

Find the zeros of 6x^2=27

The zeros of 6x^2=27 are x= 3/(sqrt(2)),x=-3/(sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

6 x^{2} = 27

x = \frac{3}{2}, x = - \frac{3}{2}

Decimal Notation

x = 2.12132 \dots, x = - 2.12132 \dots

Solution steps

6 x^{2} = 27

Divide both sides by

6

x^{2} = \frac{9}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{9}{2}, x = - \frac{9}{2}

\frac{9}{2} = \frac{3}{2}

- \frac{9}{2} = - \frac{3}{2}

x = \frac{3}{2}, x = - \frac{3}{2}

22 < \frac{m ^{2} + 7}{4} < 32

- 3 (\frac{4}{9})^{0}

2 x^{2} + 6 x + 4 = 0

\frac{x + 5}{x + 7} < 2

8 x^{2} - 35 x + 38 = 0

What are the solutions to the equation 6x^2=27 ?
The solutions to the equation 6x^2=27 are x= 3/(sqrt(2)),x=-3/(sqrt(2))
Find the zeros of 6x^2=27
The zeros of 6x^2=27 are x= 3/(sqrt(2)),x=-3/(sqrt(2))