What are the solutions to the equation x^2+99=20x ?

The solutions to the equation x^2+99=20x are x=11,x=9

Find the zeros of x^2+99=20x

The zeros of x^2+99=20x are x=11,x=9

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x^{2} + 99 = 20 x

x = 11, x = 9

Solution steps

x^{2} + 99 = 20 x

Move

20 x

to the left side

x^{2} + 99 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 20 x + 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 99}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 99 = 2

x_{1, 2} = \frac{- ( - 20 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2}{2 \cdot 1} : 11

x = \frac{- ( - 20 ) - 2}{2 \cdot 1} : 9

The solutions to the quadratic equation are:

x = 11, x = 9

x^{2} + 2 x (0.994987437) = 0.01

2 y = y^{2}

(z + 3) (z - 7) = 0

2 x^{2} - 7 x = - 3

- \frac{4}{3} + 2

What are the solutions to the equation x^2+99=20x ?
The solutions to the equation x^2+99=20x are x=11,x=9
Find the zeros of x^2+99=20x
The zeros of x^2+99=20x are x=11,x=9