What is ((x-2))/(x^2-3x-10)>= 0 ?

The solution to ((x-2))/(x^2-3x-10)>= 0 is -2 5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-2))/(x^2-3x-10)>= 0

\frac{( x - 2 )}{x ^{2} - 3 x - 10} \geq 0

- 2 < x \leq 2 or x > 5

Interval Notation

(- 2, 2] \cup (5, \infty)

Solution steps

\frac{x - 2}{x ^{2} - 3 x - 10} \geq 0

Factor

\frac{x - 2}{x ^{2} - 3 x - 10} : \frac{x - 2}{( x + 2 ) ( x - 5 )}

\frac{x - 2}{( x + 2 ) ( x - 5 )} \geq 0

Identify the intervals

- 2 < x \leq 2 or x > 5

x^{4} - 256

\frac{19 n ^{3} + 38 n ^{2}}{- 57 n ^{3} + 38 n ^{2}}

\frac{1}{4} n^{2} + \frac{3}{2} n = - \frac{3}{4}

- 2 x^{2} + 6 x - 4 = 0

x^{2} + 12 x y + 35 y^{2}

What is ((x-2))/(x^2-3x-10)>= 0 ?
The solution to ((x-2))/(x^2-3x-10)>= 0 is -2<x<= 2\lor x>5