What are the solutions to the equation -2x^2+6x-4=0 ?

The solutions to the equation -2x^2+6x-4=0 are x=1,x=2

Find the zeros of -2x^2+6x-4=0

The zeros of -2x^2+6x-4=0 are x=1,x=2

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- 2 x^{2} + 6 x - 4 = 0

x = 1, x = 2

Solution steps

- 2 x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) ( - 4 )}{2 ( - 2 )}

6^{2} - 4 (- 2) (- 4) = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 ( - 2 )}, x_{2} = \frac{- 6 - 2}{2 ( - 2 )}

x = \frac{- 6 + 2}{2 ( - 2 )} : 1

x = \frac{- 6 - 2}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = 1, x = 2

x^{2} + 12 x y + 35 y^{2}

4 v^{3} - 12 v^{2} - 5 v + 15

- ln (3 + 32)

x^{2} + 7 x = 60

- 8 - 14

What are the solutions to the equation -2x^2+6x-4=0 ?
The solutions to the equation -2x^2+6x-4=0 are x=1,x=2
Find the zeros of -2x^2+6x-4=0
The zeros of -2x^2+6x-4=0 are x=1,x=2