What is x^3-4x^2>4x ?

The solution to x^3-4x^2>4x is 2(1-sqrt(2)) 2(1+sqrt(2))

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x^3-4x^2>4x

x^{3} - 4 x^{2} > 4 x

2 (1 - 2) < x < 0 or x > 2 (1 + 2)

Interval Notation

(2 (1 - 2), 0) \cup (2 (1 + 2), \infty)

Decimal Notation

- 0.82842 \dots < x < 0 or x > 4.82842 \dots

Solution steps

x^{3} - 4 x^{2} > 4 x

Rewrite in standard form

x^{3} - 4 x^{2} - 4 x > 0

Factor

x^{3} - 4 x^{2} - 4 x : x (x - 2 (1 + 2)) (x - 2 (1 - 2))

x (x - 2 (1 + 2)) (x - 2 (1 - 2)) > 0

Identify the intervals

2 (1 - 2) < x < 0 or x > 2 (1 + 2)

0 = 19.8 (- 66 - \frac{( - 1825 - 5.2 x )}{19.8})

4 x^{2} - 12 x = - 13

\frac{x}{5} - 3 = 8

2 (2 x^{2} - 3 x) \geq 9

4 x - (7 x + 3) \leq 8 x + 2 (x - 3)

What is x^3-4x^2>4x ?
The solution to x^3-4x^2>4x is 2(1-sqrt(2))<x<0\lor x>2(1+sqrt(2))