What is 4x-(7x+3)<= 8x+2(x-3) ?

The solution to 4x-(7x+3) = 3/13

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4x-(7x+3)<= 8x+2(x-3)

4 x - (7 x + 3) \leq 8 x + 2 (x - 3)

x \geq \frac{3}{13}

Interval Notation

[\frac{3}{13}, \infty)

Decimal Notation

x \geq 0.23076 \dots

Solution steps

4 x - (7 x + 3) \leq 8 x + 2 (x - 3)

Expand

2 (x - 3) : 2 x - 6

- 3 x - 3 \leq 8 x + 2 x - 6

Add similar elements:

8 x + 2 x = 10 x

- 3 x - 3 \leq 10 x - 6

Expand

4 x - (7 x + 3) : - 3 x - 3

- 3 x - 3 \leq 10 x - 6

Move

3

to the right side

- 3 x \leq 10 x - 3

Move

10 x

to the left side

- 13 x \leq - 3

Multiply both sides by

- 1

13 x \geq 3

Divide both sides by

13

x \geq \frac{3}{13}

∣ 3 - 2 x ∣ < 5

- x^{2} - 2 x + 5 = 0

A = 9000 (1 + 8.75)^{15}

6 x^{2} + 11 x + 4 = 0

4 \cdot \frac{5}{7}

What is 4x-(7x+3)<= 8x+2(x-3) ?
The solution to 4x-(7x+3)<= 8x+2(x-3) is x>= 3/13