What are the solutions to the equation 9a^2+10a=-6 ?

The solutions to the equation 9a^2+10a=-6 are a=-5/9+i(sqrt(29))/9 ,a=-5/9-i(sqrt(29))/9

Find the zeros of 9a^2+10a=-6

The zeros of 9a^2+10a=-6 are a=-5/9+i(sqrt(29))/9 ,a=-5/9-i(sqrt(29))/9

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9 a^{2} + 10 a = - 6

a = - \frac{5}{9} + i \frac{29}{9}, a = - \frac{5}{9} - i \frac{29}{9}

Solution steps

9 a^{2} + 10 a = - 6

Move

6

to the left side

9 a^{2} + 10 a + 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 9 \cdot 6}{2 \cdot 9}

Simplify

1 0^{2} - 4 \cdot 9 \cdot 6 : 229 i

a_{1, 2} = \frac{- 10 \pm 2 29 i}{2 \cdot 9}

Separate the solutions

a_{1} = \frac{- 10 + 2 29 i}{2 \cdot 9}, a_{2} = \frac{- 10 - 2 29 i}{2 \cdot 9}

a = \frac{- 10 + 2 29 i}{2 \cdot 9} : - \frac{5}{9} + i \frac{29}{9}

a = \frac{- 10 - 2 29 i}{2 \cdot 9} : - \frac{5}{9} - i \frac{29}{9}

The solutions to the quadratic equation are:

a = - \frac{5}{9} + i \frac{29}{9}, a = - \frac{5}{9} - i \frac{29}{9}

8 x^{2} - 5 x + 2 = 0

4.5 x + 27 = - 9

- \frac{5}{4} + \frac{1}{6}

f (n) = \frac{n ^{3} - n}{n ^{2} - 5 n - 6}

\frac{5}{3} + (- \frac{7}{6})

What are the solutions to the equation 9a^2+10a=-6 ?
The solutions to the equation 9a^2+10a=-6 are a=-5/9+i(sqrt(29))/9 ,a=-5/9-i(sqrt(29))/9
Find the zeros of 9a^2+10a=-6
The zeros of 9a^2+10a=-6 are a=-5/9+i(sqrt(29))/9 ,a=-5/9-i(sqrt(29))/9