What are the solutions to the equation u^2=40-6u ?

The solutions to the equation u^2=40-6u are u=4,u=-10

Find the zeros of u^2=40-6u

The zeros of u^2=40-6u are u=4,u=-10

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u^{2} = 40 - 6 u

u = 4, u = - 10

Solution steps

u^{2} = 40 - 6 u

Move

6 u

to the left side

u^{2} + 6 u = 40

Move

40

to the left side

u^{2} + 6 u - 40 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 40) = 14

u_{1, 2} = \frac{- 6 \pm 14}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 6 + 14}{2 \cdot 1}, u_{2} = \frac{- 6 - 14}{2 \cdot 1}

u = \frac{- 6 + 14}{2 \cdot 1} : 4

u = \frac{- 6 - 14}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

u = 4, u = - 10

w^{2} + 4 w + 4 = 0

X^{2} > 1

- 13 = y - 4

k + 6 > - 20

\frac{1}{2} x^{2} - 1 x - 4 = 0

What are the solutions to the equation u^2=40-6u ?
The solutions to the equation u^2=40-6u are u=4,u=-10
Find the zeros of u^2=40-6u
The zeros of u^2=40-6u are u=4,u=-10