What are the solutions to the equation z^2+4=0 ?

The solutions to the equation z^2+4=0 are z=2i,z=-2i

Find the zeros of z^2+4=0

The zeros of z^2+4=0 are z=2i,z=-2i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

z^{2} + 4 = 0

z = 2 i, z = - 2 i

Solution steps

z^{2} + 4 = 0

Move

4

to the right side

z^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = - 4, z = - - 4

- 4 = 2 i

- - 4 = - 2 i

z = 2 i, z = - 2 i

y, x^{3} - 3 x^{2} y = c

3 ∣ x - 8 ∣ = 12

(1 + \frac{0.02}{4})^{4} - 1

x^{2} + x = 7

\frac{( 2 x + 7 )}{3} - \frac{( 3 x - 6 )}{4} - \frac{( x + 3 )}{2} = \frac{( 4 x + 9 )}{6}

What are the solutions to the equation z^2+4=0 ?
The solutions to the equation z^2+4=0 are z=2i,z=-2i
Find the zeros of z^2+4=0
The zeros of z^2+4=0 are z=2i,z=-2i