What are the solutions to the equation (v-9)(v+3)=0 ?

The solutions to the equation (v-9)(v+3)=0 are v=9,v=-3

Find the zeros of (v-9)(v+3)=0

The zeros of (v-9)(v+3)=0 are v=9,v=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(v - 9) (v + 3) = 0

v = 9, v = - 3

Solution steps

(v - 9) (v + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v - 9 = 0 or v + 3 = 0

Solve

v - 9 = 0 : v = 9

Solve

v + 3 = 0 : v = - 3

The solutions to the quadratic equation are:

v = 9, v = - 3

16 pq r - 9 p s t

2 (x + 1)^{2} = - 8

216 w^{4} - 125 w

5 - 45 x^{5}

1 > \frac{y}{2} - 1

What are the solutions to the equation (v-9)(v+3)=0 ?
The solutions to the equation (v-9)(v+3)=0 are v=9,v=-3
Find the zeros of (v-9)(v+3)=0
The zeros of (v-9)(v+3)=0 are v=9,v=-3