What are the solutions to the equation 6x^2-4=0 ?

The solutions to the equation 6x^2-4=0 are x=sqrt(2/3),x=-sqrt(2/3)

Find the zeros of 6x^2-4=0

The zeros of 6x^2-4=0 are x=sqrt(2/3),x=-sqrt(2/3)

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6 x^{2} - 4 = 0

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 0.81649 \dots, x = - 0.81649 \dots

Solution steps

6 x^{2} - 4 = 0

Move

4

to the right side

6 x^{2} = 4

Divide both sides by

6

x^{2} = \frac{2}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{2}{3}, x = - \frac{2}{3}

(x^{\frac{4}{3}}) (x^{- \frac{2}{5}}) (x^{\frac{3}{5}})

\frac{1}{2} - x < 2

12 x y^{2} - 108 x

8 + x^{3}

- (y - 3) y = 0

What are the solutions to the equation 6x^2-4=0 ?
The solutions to the equation 6x^2-4=0 are x=sqrt(2/3),x=-sqrt(2/3)
Find the zeros of 6x^2-4=0
The zeros of 6x^2-4=0 are x=sqrt(2/3),x=-sqrt(2/3)