What is (x-2)/(x^2-3x-10)>= 0 ?

The solution to (x-2)/(x^2-3x-10)>= 0 is -2 5

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(x-2)/(x^2-3x-10)>= 0

\frac{x - 2}{x ^{2} - 3 x - 10} \geq 0

- 2 < x \leq 2 or x > 5

Interval Notation

(- 2, 2] \cup (5, \infty)

Solution steps

\frac{x - 2}{x ^{2} - 3 x - 10} \geq 0

Factor

\frac{x - 2}{x ^{2} - 3 x - 10} : \frac{x - 2}{( x + 2 ) ( x - 5 )}

\frac{x - 2}{( x + 2 ) ( x - 5 )} \geq 0

Identify the intervals

- 2 < x \leq 2 or x > 5

\frac{8 x ^{3} y ^{- 5}}{4 x ^{- 1} y ^{2}}

x - 7 < 3 (x + 1)

f = \frac{5 ( - 1 ) + 3}{3 ( - 1 ) - 4}

2 (x + 6)^{2} = 36

125 x^{3} - 64

What is (x-2)/(x^2-3x-10)>= 0 ?
The solution to (x-2)/(x^2-3x-10)>= 0 is -2<x<= 2\lor x>5