What are the solutions to the equation x^2-2x=53 ?

The solutions to the equation x^2-2x=53 are x=1+3sqrt(6),x=1-3sqrt(6)

Find the zeros of x^2-2x=53

The zeros of x^2-2x=53 are x=1+3sqrt(6),x=1-3sqrt(6)

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x^{2} - 2 x = 53

x = 1 + 36, x = 1 - 36

Decimal Notation

x = 8.34846 \dots, x = - 6.34846 \dots

Solution steps

x^{2} - 2 x = 53

Move

53

to the left side

x^{2} - 2 x - 53 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 53 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 53) = 66

x_{1, 2} = \frac{- ( - 2 ) \pm 6 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6 6}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 6 6}{2 \cdot 1}

x = \frac{- ( - 2 ) + 6 6}{2 \cdot 1} : 1 + 36

x = \frac{- ( - 2 ) - 6 6}{2 \cdot 1} : 1 - 36

The solutions to the quadratic equation are:

x = 1 + 36, x = 1 - 36

(x \frac{3}{4})^{4}

8 - 12 x = - 2 x - 27

6 x^{2} - 78 x + 240 = 0

2 x^{2} - 5 x - 7

36 = 3 y

What are the solutions to the equation x^2-2x=53 ?
The solutions to the equation x^2-2x=53 are x=1+3sqrt(6),x=1-3sqrt(6)
Find the zeros of x^2-2x=53
The zeros of x^2-2x=53 are x=1+3sqrt(6),x=1-3sqrt(6)