What are the solutions to the equation 7x^2+1=0 ?

The solutions to the equation 7x^2+1=0 are x= 1/(sqrt(7))i,x=-1/(sqrt(7))i

Find the zeros of 7x^2+1=0

The zeros of 7x^2+1=0 are x= 1/(sqrt(7))i,x=-1/(sqrt(7))i

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7 x^{2} + 1 = 0

x = \frac{1}{7} i, x = - \frac{1}{7} i

Solution steps

7 x^{2} + 1 = 0

Move

1

to the right side

7 x^{2} = - 1

Divide both sides by

7

x^{2} = - \frac{1}{7}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{7}, x = - - \frac{1}{7}

- \frac{1}{7} = \frac{1}{7} i

- - \frac{1}{7} = - \frac{1}{7} i

x = \frac{1}{7} i, x = - \frac{1}{7} i

\frac{a ^{2} - 1}{a ^{3} + 1} \cdot \frac{a ^{2} - a + 1}{a ^{2} + 2 a + 1}

- 80 = x^{2} + 160 x - 6400

6 t + 3 (5 t - 4) = 12 (2 t - 5)

0.053 = 1.6365 x + 0.1895

4 - ∣ x - 12 ∣ < 4

What are the solutions to the equation 7x^2+1=0 ?
The solutions to the equation 7x^2+1=0 are x= 1/(sqrt(7))i,x=-1/(sqrt(7))i
Find the zeros of 7x^2+1=0
The zeros of 7x^2+1=0 are x= 1/(sqrt(7))i,x=-1/(sqrt(7))i