What are the solutions to the equation 6x^2+12x=5x-2 ?

The solutions to the equation 6x^2+12x=5x-2 are x=-1/2 ,x=-2/3

Find the zeros of 6x^2+12x=5x-2

The zeros of 6x^2+12x=5x-2 are x=-1/2 ,x=-2/3

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6 x^{2} + 12 x = 5 x - 2

x = - \frac{1}{2}, x = - \frac{2}{3}

Solution steps

6 x^{2} + 12 x = 5 x - 2

Move

2

to the left side

6 x^{2} + 12 x + 2 = 5 x

Move

5 x

to the left side

6 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 6 \cdot 2}{2 \cdot 6}

7^{2} - 4 \cdot 6 \cdot 2 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 6}, x_{2} = \frac{- 7 - 1}{2 \cdot 6}

x = \frac{- 7 + 1}{2 \cdot 6} : - \frac{1}{2}

x = \frac{- 7 - 1}{2 \cdot 6} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{2}{3}

x^{4} y^{2} - x^{2} y^{4}

(x^{2})^{\frac{1}{3}}

x^{2} - 4 x < 0

∣ x - 1 ∣ > 2

9 x^{2} + 6 x = - 2

What are the solutions to the equation 6x^2+12x=5x-2 ?
The solutions to the equation 6x^2+12x=5x-2 are x=-1/2 ,x=-2/3
Find the zeros of 6x^2+12x=5x-2
The zeros of 6x^2+12x=5x-2 are x=-1/2 ,x=-2/3