What are the solutions to the equation 3x^2-8x+3=0 ?

The solutions to the equation 3x^2-8x+3=0 are x=(4+sqrt(7))/3 ,x=(4-sqrt(7))/3

Find the zeros of 3x^2-8x+3=0

The zeros of 3x^2-8x+3=0 are x=(4+sqrt(7))/3 ,x=(4-sqrt(7))/3

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3 x^{2} - 8 x + 3 = 0

x = \frac{4 + 7}{3}, x = \frac{4 - 7}{3}

Decimal Notation

x = 2.21525 \dots, x = 0.45141 \dots

Solution steps

3 x^{2} - 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 3}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 \cdot 3 = 27

x_{1, 2} = \frac{- ( - 8 ) \pm 2 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 7}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2 7}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2 7}{2 \cdot 3} : \frac{4 + 7}{3}

x = \frac{- ( - 8 ) - 2 7}{2 \cdot 3} : \frac{4 - 7}{3}

The solutions to the quadratic equation are:

x = \frac{4 + 7}{3}, x = \frac{4 - 7}{3}

(7 + 3) (7 + 43)

7 - \frac{x}{7} = - 2

- 16 x^{2} + 3 x + 32 = 0

\frac{10 + 10 i}{1 + i}

4 y^{2} - 8 y + 3

What are the solutions to the equation 3x^2-8x+3=0 ?
The solutions to the equation 3x^2-8x+3=0 are x=(4+sqrt(7))/3 ,x=(4-sqrt(7))/3
Find the zeros of 3x^2-8x+3=0
The zeros of 3x^2-8x+3=0 are x=(4+sqrt(7))/3 ,x=(4-sqrt(7))/3