What are the solutions to the equation 12x^2+3x-3=0 ?

The solutions to the equation 12x^2+3x-3=0 are x=(-1+sqrt(17))/8 ,x=-(1+sqrt(17))/8

Find the zeros of 12x^2+3x-3=0

The zeros of 12x^2+3x-3=0 are x=(-1+sqrt(17))/8 ,x=-(1+sqrt(17))/8

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12 x^{2} + 3 x - 3 = 0

x = \frac{- 1 + 17}{8}, x = - \frac{1 + 17}{8}

Decimal Notation

x = 0.39038 \dots, x = - 0.64038 \dots

Solution steps

12 x^{2} + 3 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 12 ( - 3 )}{2 \cdot 12}

3^{2} - 4 \cdot 12 (- 3) = 317

x_{1, 2} = \frac{- 3 \pm 3 17}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 3 + 3 17}{2 \cdot 12}, x_{2} = \frac{- 3 - 3 17}{2 \cdot 12}

x = \frac{- 3 + 3 17}{2 \cdot 12} : \frac{- 1 + 17}{8}

x = \frac{- 3 - 3 17}{2 \cdot 12} : - \frac{1 + 17}{8}

The solutions to the quadratic equation are:

x = \frac{- 1 + 17}{8}, x = - \frac{1 + 17}{8}

x + 16 \leq 0

x^{2} = 12 x - 40

y^{2} - 5 y = 0

4 (y + 2) - y = 2 (y - 1) + 9

2 x^{3} - 3 x^{2} + 1

What are the solutions to the equation 12x^2+3x-3=0 ?
The solutions to the equation 12x^2+3x-3=0 are x=(-1+sqrt(17))/8 ,x=-(1+sqrt(17))/8
Find the zeros of 12x^2+3x-3=0
The zeros of 12x^2+3x-3=0 are x=(-1+sqrt(17))/8 ,x=-(1+sqrt(17))/8