What are the solutions to the equation n^2+3n-12=6 ?

The solutions to the equation n^2+3n-12=6 are n=3,n=-6

Find the zeros of n^2+3n-12=6

The zeros of n^2+3n-12=6 are n=3,n=-6

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n^{2} + 3 n - 12 = 6

n = 3, n = - 6

Solution steps

n^{2} + 3 n - 12 = 6

Move

6

to the left side

n^{2} + 3 n - 18 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 18) = 9

n_{1, 2} = \frac{- 3 \pm 9}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 3 + 9}{2 \cdot 1}, n_{2} = \frac{- 3 - 9}{2 \cdot 1}

n = \frac{- 3 + 9}{2 \cdot 1} : 3

n = \frac{- 3 - 9}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

n = 3, n = - 6

∣ 9 x - 8 ∣ = 0

16 z^{2} + 61 = 64 z

88 = x^{2}

5 \cdot 9

15!

What are the solutions to the equation n^2+3n-12=6 ?
The solutions to the equation n^2+3n-12=6 are n=3,n=-6
Find the zeros of n^2+3n-12=6
The zeros of n^2+3n-12=6 are n=3,n=-6