What are the solutions to the equation 12x^2+17x=5 ?

The solutions to the equation 12x^2+17x=5 are x= 1/4 ,x=-5/3

Find the zeros of 12x^2+17x=5

The zeros of 12x^2+17x=5 are x= 1/4 ,x=-5/3

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12 x^{2} + 17 x = 5

x = \frac{1}{4}, x = - \frac{5}{3}

Solution steps

12 x^{2} + 17 x = 5

Move

5

to the left side

12 x^{2} + 17 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 12 ( - 5 )}{2 \cdot 12}

1 7^{2} - 4 \cdot 12 (- 5) = 23

x_{1, 2} = \frac{- 17 \pm 23}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 17 + 23}{2 \cdot 12}, x_{2} = \frac{- 17 - 23}{2 \cdot 12}

x = \frac{- 17 + 23}{2 \cdot 12} : \frac{1}{4}

x = \frac{- 17 - 23}{2 \cdot 12} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{5}{3}

\frac{3 x - 2}{7} = \frac{6 x - 5}{13}

x + 5 < 20

x^{2} + 3 x - 54 < 0

∣ 5 x - 7 ∣ \leq 3

6 a^{2} + 37 ab + 6 b^{2}

What are the solutions to the equation 12x^2+17x=5 ?
The solutions to the equation 12x^2+17x=5 are x= 1/4 ,x=-5/3
Find the zeros of 12x^2+17x=5
The zeros of 12x^2+17x=5 are x= 1/4 ,x=-5/3