What are the solutions to the equation 4x^2+10x-1476=0 ?

The solutions to the equation 4x^2+10x-1476=0 are x=18,x=-41/2

Find the zeros of 4x^2+10x-1476=0

The zeros of 4x^2+10x-1476=0 are x=18,x=-41/2

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4 x^{2} + 10 x - 1476 = 0

x = 18, x = - \frac{41}{2}

Decimal Notation

x = 18, x = - 20.5

Solution steps

4 x^{2} + 10 x - 1476 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 4 ( - 1476 )}{2 \cdot 4}

1 0^{2} - 4 \cdot 4 (- 1476) = 154

x_{1, 2} = \frac{- 10 \pm 154}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 10 + 154}{2 \cdot 4}, x_{2} = \frac{- 10 - 154}{2 \cdot 4}

x = \frac{- 10 + 154}{2 \cdot 4} : 18

x = \frac{- 10 - 154}{2 \cdot 4} : - \frac{41}{2}

The solutions to the quadratic equation are:

x = 18, x = - \frac{41}{2}

1 2^{2} + 4^{2} = c^{2}

2 x - 6 = x^{2} - 4 x + 2

- 2 \leq \frac{x - 5}{2} < 3

8 ∣ x - 3 ∣ = - 24

16 n^{2} - 1

What are the solutions to the equation 4x^2+10x-1476=0 ?
The solutions to the equation 4x^2+10x-1476=0 are x=18,x=-41/2
Find the zeros of 4x^2+10x-1476=0
The zeros of 4x^2+10x-1476=0 are x=18,x=-41/2