What is the answer to (1-6x)/2-(2x+19}{12}=\frac{23-2x)/3 ?

The answer to (1-6x)/2-(2x+19}{12}=\frac{23-2x)/3 is x=-7/2

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(1-6x)/2-(2x+19}{12}=\frac{23-2x)/3

\frac{1 - 6 x}{2} - \frac{2 x + 19}{12} = \frac{23 - 2 x}{3}

x = - \frac{7}{2}

Decimal Notation

x = - 3.5

Solution steps

\frac{1 - 6 x}{2} - \frac{2 x + 19}{12} = \frac{23 - 2 x}{3}

Multiply by LCM

6 (- 6 x + 1) - (2 x + 19) = 4 (- 2 x + 23)

Expand

6 (- 6 x + 1) - (2 x + 19) : - 38 x - 13

Expand

4 (- 2 x + 23) : - 8 x + 92

- 38 x - 13 = - 8 x + 92

Move

13

to the right side

- 38 x = - 8 x + 105

Move

8 x

to the left side

- 30 x = 105

Divide both sides by

- 30

x = - \frac{7}{2}

x^{2} + 11 x = 7 x + 21

5 x - 3 (3 x - 3 + 2 x) \geq 2 (3 x - 20 + 4 x)

\frac{100 !}{98 !}

e^{- 0.6}

What is the answer to (1-6x)/2-(2x+19}{12}=\frac{23-2x)/3 ?
The answer to (1-6x)/2-(2x+19}{12}=\frac{23-2x)/3 is x=-7/2
Solve for x: (1-6x)/2-(2x+19}{12}=\frac{23-2x)/3
The solution is x=-7/2