What are the solutions to the equation 8x^2+32x+34=0 ?

The solutions to the equation 8x^2+32x+34=0 are x=-2+i 1/2 ,x=-2-i 1/2

Find the zeros of 8x^2+32x+34=0

The zeros of 8x^2+32x+34=0 are x=-2+i 1/2 ,x=-2-i 1/2

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8 x^{2} + 32 x + 34 = 0

x = - 2 + i \frac{1}{2}, x = - 2 - i \frac{1}{2}

Solution steps

8 x^{2} + 32 x + 34 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 8 \cdot 34}{2 \cdot 8}

Simplify

3 2^{2} - 4 \cdot 8 \cdot 34 : 8 i

x_{1, 2} = \frac{- 32 \pm 8 i}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 32 + 8 i}{2 \cdot 8}, x_{2} = \frac{- 32 - 8 i}{2 \cdot 8}

x = \frac{- 32 + 8 i}{2 \cdot 8} : - 2 + i \frac{1}{2}

x = \frac{- 32 - 8 i}{2 \cdot 8} : - 2 - i \frac{1}{2}

The solutions to the quadratic equation are:

x = - 2 + i \frac{1}{2}, x = - 2 - i \frac{1}{2}

6 (- 2)^{2} + 6 (- 2) - 12

\frac{2 x - 5}{3} - \frac{5 x - 3}{4} + 2 + \frac{2}{3} = 0

x^{2} - 7 x y + 6 y^{2}

6 (\frac{1}{3})^{1}

\frac{3}{4} \cdot 8

What are the solutions to the equation 8x^2+32x+34=0 ?
The solutions to the equation 8x^2+32x+34=0 are x=-2+i 1/2 ,x=-2-i 1/2
Find the zeros of 8x^2+32x+34=0
The zeros of 8x^2+32x+34=0 are x=-2+i 1/2 ,x=-2-i 1/2