What is the answer to (2x-5)/3-(5x-3)/4+2+2/3 =0 ?

The answer to (2x-5)/3-(5x-3)/4+2+2/3 =0 is x=3

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(2x-5)/3-(5x-3)/4+2+2/3 =0

\frac{2 x - 5}{3} - \frac{5 x - 3}{4} + 2 + \frac{2}{3} = 0

x = 3

Solution steps

\frac{2 x - 5}{3} - \frac{5 x - 3}{4} + 2 + \frac{2}{3} = 0

Combine the fractions

2 + \frac{2}{3} : \frac{8}{3}

\frac{8}{3} + \frac{2 x - 5}{3} - \frac{5 x - 3}{4} = 0

Multiply by LCM

32 + 4 (2 x - 5) - 3 (5 x - 3) = 0

Expand

32 + 4 (2 x - 5) - 3 (5 x - 3) : - 7 x + 21

- 7 x + 21 = 0

Move

21

to the right side

- 7 x = - 21

Divide both sides by

- 7

x = 3

x^{2} - 7 x y + 6 y^{2}

6 (\frac{1}{3})^{1}

\frac{3}{4} \cdot 8

4 (u + 1) + u = 8 (u - 1) + 6

(2 x - 1) (x + 3) = 0

What is the answer to (2x-5)/3-(5x-3)/4+2+2/3 =0 ?
The answer to (2x-5)/3-(5x-3)/4+2+2/3 =0 is x=3
Solve for x: (2x-5)/3-(5x-3)/4+2+2/3 =0
The solution is x=3