What are the solutions to the equation (2x-1)(x+3)=0 ?

The solutions to the equation (2x-1)(x+3)=0 are x= 1/2 ,x=-3

Find the zeros of (2x-1)(x+3)=0

The zeros of (2x-1)(x+3)=0 are x= 1/2 ,x=-3

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(2 x - 1) (x + 3) = 0

x = \frac{1}{2}, x = - 3

Decimal Notation

x = 0.5, x = - 3

Solution steps

(2 x - 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 1 = 0 or x + 3 = 0

Solve

2 x - 1 = 0 : x = \frac{1}{2}

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 3

x^{2} + 5 x \geq 6

x^{2} + 12 x + 5 = - 15

y + 2 \geq 1

(3 z - 7)^{2} + 49 = 0

2 x^{2} + 5 x + \frac{25}{8} = 0

What are the solutions to the equation (2x-1)(x+3)=0 ?
The solutions to the equation (2x-1)(x+3)=0 are x= 1/2 ,x=-3
Find the zeros of (2x-1)(x+3)=0
The zeros of (2x-1)(x+3)=0 are x= 1/2 ,x=-3