What are the solutions to the equation 2x^2+5x+25/8 =0 ?

The solutions to the equation 2x^2+5x+25/8 =0 are x=-5/4

Find the zeros of 2x^2+5x+25/8 =0

The zeros of 2x^2+5x+25/8 =0 are x=-5/4

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2 x^{2} + 5 x + \frac{25}{8} = 0

x = - \frac{5}{4}

Decimal Notation

x = - 1.25

Solution steps

2 x^{2} + 5 x + \frac{25}{8} = 0

Multiply both sides by

8

16 x^{2} + 40 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 16 \cdot 25}{2 \cdot 16}

4 0^{2} - 4 \cdot 16 \cdot 25 = 0

x_{1, 2} = \frac{- 40 \pm 0}{2 \cdot 16}

x = \frac{- 40}{2 \cdot 16}

\frac{- 40}{2 \cdot 16} = - \frac{5}{4}

x = - \frac{5}{4}

The solution to the quadratic equation is:

x = - \frac{5}{4}

y, 2 - x y g = x^{2} - 4

(2 x - 5)^{2} = 81

4^{x} > 2^{x}

8 x^{2} - x + 2 = 0

7 x^{2} + 7 x + 7

What are the solutions to the equation 2x^2+5x+25/8 =0 ?
The solutions to the equation 2x^2+5x+25/8 =0 are x=-5/4
Find the zeros of 2x^2+5x+25/8 =0
The zeros of 2x^2+5x+25/8 =0 are x=-5/4