What are the solutions to the equation x^2+12x+37=0 ?

The solutions to the equation x^2+12x+37=0 are x=-6+i,x=-6-i

Find the zeros of x^2+12x+37=0

The zeros of x^2+12x+37=0 are x=-6+i,x=-6-i

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x^{2} + 12 x + 37 = 0

x = - 6 + i, x = - 6 - i

Solution steps

x^{2} + 12 x + 37 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 37}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 37 : 2 i

x_{1, 2} = \frac{- 12 \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 i}{2 \cdot 1}

x = \frac{- 12 + 2 i}{2 \cdot 1} : - 6 + i

x = \frac{- 12 - 2 i}{2 \cdot 1} : - 6 - i

The solutions to the quadratic equation are:

x = - 6 + i, x = - 6 - i

a - \frac{a}{3} + \frac{a}{5} = 26

4 (x + 10)^{2} + 14 = 26

6 p^{2} = - 31 p - 5

0 = 32 - 50 x^{2}

x^{12} - 64

What are the solutions to the equation x^2+12x+37=0 ?
The solutions to the equation x^2+12x+37=0 are x=-6+i,x=-6-i
Find the zeros of x^2+12x+37=0
The zeros of x^2+12x+37=0 are x=-6+i,x=-6-i