What are the solutions to the equation x^2+40x-400=0 ?

The solutions to the equation x^2+40x-400=0 are x=20(sqrt(2)-1),x=-20(1+sqrt(2))

Find the zeros of x^2+40x-400=0

The zeros of x^2+40x-400=0 are x=20(sqrt(2)-1),x=-20(1+sqrt(2))

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x^{2} + 40 x - 400 = 0

x = 20 (2 - 1), x = - 20 (1 + 2)

Decimal Notation

x = 8.28427 \dots, x = - 48.28427 \dots

Solution steps

x^{2} + 40 x - 400 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot ( - 400 )}{2 \cdot 1}

4 0^{2} - 4 \cdot 1 \cdot (- 400) = 402

x_{1, 2} = \frac{- 40 \pm 40 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 40 + 40 2}{2 \cdot 1}, x_{2} = \frac{- 40 - 40 2}{2 \cdot 1}

x = \frac{- 40 + 40 2}{2 \cdot 1} : 20 (2 - 1)

x = \frac{- 40 - 40 2}{2 \cdot 1} : - 20 (1 + 2)

The solutions to the quadratic equation are:

x = 20 (2 - 1), x = - 20 (1 + 2)

5 x^{2} - x + 6 = 0

4 = \frac{2}{3} (2 x - 9)

\frac{20}{1140} + \frac{24}{1140} + \frac{10}{1140}

5 h + 2 (11 - h) = - 5

What are the solutions to the equation x^2+40x-400=0 ?
The solutions to the equation x^2+40x-400=0 are x=20(sqrt(2)-1),x=-20(1+sqrt(2))
Find the zeros of x^2+40x-400=0
The zeros of x^2+40x-400=0 are x=20(sqrt(2)-1),x=-20(1+sqrt(2))