What are the solutions to the equation 2r^2-r-10=0 ?

The solutions to the equation 2r^2-r-10=0 are r= 5/2 ,r=-2

Find the zeros of 2r^2-r-10=0

The zeros of 2r^2-r-10=0 are r= 5/2 ,r=-2

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2 r^{2} - r - 10 = 0

r = \frac{5}{2}, r = - 2

Decimal Notation

r = 2.5, r = - 2

Solution steps

2 r^{2} - r - 10 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 10) = 9

r_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 2}

Separate the solutions

r_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 2}, r_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 2}

r = \frac{- ( - 1 ) + 9}{2 \cdot 2} : \frac{5}{2}

r = \frac{- ( - 1 ) - 9}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

r = \frac{5}{2}, r = - 2

\frac{68}{( 1 - i ) ( 2 - i ) ( 3 - i )}

\frac{48}{2}

3 (3 y - 8) = 30

∣ x + 1 ∣ ∣ x + 2 ∣ = 3

\frac{x - 7}{x + 5} \geq - 3

What are the solutions to the equation 2r^2-r-10=0 ?
The solutions to the equation 2r^2-r-10=0 are r= 5/2 ,r=-2
Find the zeros of 2r^2-r-10=0
The zeros of 2r^2-r-10=0 are r= 5/2 ,r=-2