What are the solutions to the equation -0.7t^2+35t=0 ?

The solutions to the equation -0.7t^2+35t=0 are t=0,t=50

Find the zeros of -0.7t^2+35t=0

The zeros of -0.7t^2+35t=0 are t=0,t=50

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- 0.7 t^{2} + 35 t = 0

t = 0, t = 50

Solution steps

- 0.7 t^{2} + 35 t = 0

Multiply both sides by

10

- 7 t^{2} + 350 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 350 \pm 35 0 ^{2} - 4 ( - 7 ) \cdot 0}{2 ( - 7 )}

35 0^{2} - 4 (- 7) \cdot 0 = 350

t_{1, 2} = \frac{- 350 \pm 350}{2 ( - 7 )}

Separate the solutions

t_{1} = \frac{- 350 + 350}{2 ( - 7 )}, t_{2} = \frac{- 350 - 350}{2 ( - 7 )}

t = \frac{- 350 + 350}{2 ( - 7 )} : 0

t = \frac{- 350 - 350}{2 ( - 7 )} : 50

The solutions to the quadratic equation are:

t = 0, t = 50

- 3 (n - 2) \leq 24

6 m^{2} + 12 m - 144

\frac{2 x + 1}{x - 3} \leq 3

\frac{( 7 x + 8 )}{5} > \frac{( x - 3 )}{3}

2 (2 x + 1) = 30

What are the solutions to the equation -0.7t^2+35t=0 ?
The solutions to the equation -0.7t^2+35t=0 are t=0,t=50
Find the zeros of -0.7t^2+35t=0
The zeros of -0.7t^2+35t=0 are t=0,t=50