What is ((7x+8))/5 >((x-3))/3 ?

The solution to ((7x+8))/5 >((x-3))/3 is x>-39/16

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((7x+8))/5 >((x-3))/3

\frac{( 7 x + 8 )}{5} > \frac{( x - 3 )}{3}

x > - \frac{39}{16}

Interval Notation

(- \frac{39}{16}, \infty)

Decimal Notation

x > - 2.4375

Solution steps

\frac{( 7 x + 8 )}{5} > \frac{( x - 3 )}{3}

Apply fraction cross multiply: if

\frac{a}{b} = \frac{c}{d}

then

a \cdot d = b \cdot c

(7 x + 8) \cdot 3 > 5 (x - 3)

Expand

(7 x + 8) \cdot 3 : 21 x + 24

Expand

5 (x - 3) : 5 x - 15

21 x + 24 > 5 x - 15

Move

24

to the right side

21 x > 5 x - 39

Move

5 x

to the left side

16 x > - 39

Divide both sides by

16

x > - \frac{39}{16}

2 (2 x + 1) = 30

3 x^{2} + 9 x - 84

x^{2} + x - 2450 = 0

- 6 x^{3} + 3 x^{2} + 18 x

5 x - 9 = 3 (x - 2)

What is ((7x+8))/5 >((x-3))/3 ?
The solution to ((7x+8))/5 >((x-3))/3 is x>-39/16